(3z-6)/(3z^2-12)

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Solution for (3z-6)/(3z^2-12) equation: 


D( z )

3*z^2-12 = 0

3*z^2-12 = 0

3*z^2-12 = 0

3*z^2 = 12 // : 3

z^2 = 4

z^2 = 4 // ^ 1/2

abs(z) = 2

z = 2 or z = -2

z in (-oo:-2) U (-2:2) U (2:+oo)

(3*z-6)/(3*z^2-12) = 0

3*z-6 = 0 // + 6

3*z = 6 // : 3

z = 6/3

z = 2

z in { 2} 

z belongs to the empty set

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